Correct answer is D.
As, f(x) = ex Sin x
Differentiating the function with respect to ‘x’,
f’(x) = ex Cos x + Sin x ex
\(\therefore\) f’(c) = ec Cos c + Sin c ec
As, ex Cos x is continuous and derivable in R.
\(\therefore\) it is contionous on [0, π] and derivable on (0, π).
f(0) = e0 Sin (0)
= 0