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in Continuity and Differentiability by (27.4k points)
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The value of f(0), so that the function f(x) = \(\frac{(27-2x)^{1/3}-3}{9-3(243+5x)^{1/5}}\)(x ≠ 0) is continuous, is given by :

A. \(\frac{2}{5}\) 

B. 6 

C. 2 

D. 4

1 Answer

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by (27.0k points)
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Best answer

Option : (C)

(i) A function f(x) is said to be continuous at a point x = a of its domain, if 

 \(\lim\limits_{x \to a}f(x)\) = f(a)

 \(\lim\limits_{x \to a^+}f(a+h)\) = \(\lim\limits_{x \to a^-}f(a-h)\) = f(a)

(ii) \(\lim\limits_{x \to a}\{\frac{f(x)}{g(x)}\}\) = \(\frac{1}{m}\),

Where \(\lim\limits_{x \to a}f(x)\) = 1, \(\lim\limits_{x \to a}g(x)\) = m

Given :-

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