Question

If g = t ^2/3 + 4t ^-1/2, what is the value of g when t = 64?

A. \(\cfrac{31}{2}\)

B. \(\cfrac{33}{2}\)

C. 16

D. \(\cfrac{257}{16}\)

Answer 1

g = t ^2/3 + 4t ^-1/2 

= (64)^2/3 + 4 (64) ^-1/2

= [(64)^1/3] ³ + 4 \((\cfrac{1}{64})^\cfrac{1}{2}\)

= 4² + 4 (\(\cfrac{1}8\) )

= 16 + \(\cfrac{1}2\) = \(\cfrac{33}2\)