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If x-2 = 64, then x 1/3 + x0

A. 2 

B. 3 

C. 3/2 

D. 2/3

1 Answer

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Best answer

\((\cfrac{1}{8})^2\) = (8)2

\(\cfrac{1}{x}\) = 8

x = \(\cfrac{1}{8}\)

x1/3 + xo

\((\cfrac{1}{8})^{\cfrac{1}{3}}\) + \((\cfrac{1}{8})^0\)

\(\cfrac{1}{2} + 1\) = \(\cfrac{3}{2}\)

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