We have ,
\(=(\frac{1}{2})^{3}+(\frac{1}{3})^{3}-(\frac{5}{6})^{3}\,given\)
Let a = \(\frac{1}{2},\,b=\frac{1}{3},c=-\frac{5}{6},\)
then the expression becomes
\(=(\frac{1}{2})^{3}+(\frac{1}{3})^{3}-(\frac{5}{6})^{3}=a^{3}+b^{3}+c^{3}\)
Here,
\(=a+b+c=\frac{1}{2}+\frac{1}{3}-\frac{5}{6}=0\)
Hence ,