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\(\frac{{5}^{n+2}-{6} \times {5}^{n+1}}{{13 \times{5}^n-2 \times{5}^{n+1}}}\)is equal to

A. \(\frac{5}3\)

B. \(-\frac{5}3\)

C. \(\frac{3}5\)

D. \(-\frac{3}5\)

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Best answer

5n (25 – 30) / 5n (13 – 10)

= -5 / 3

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