Question

AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠FEB. If ∠LEB =35°, then ∠CFQ will be

A. 55°

B. 70°

C. 110°

D. 130°

Answer 1

Given that,

AB ‖ CD and PQ cuts them

EL is bisector of ∠FEB

∠LEB = ∠FEL = 35°

∠FEB = ∠LEB + ∠FEL

= 35° + 35°

= 70°

∠FEB = ∠EFC = 70°(Alternate angles)

∠EFC + ∠CFQ = 180°(Linear pair)

70° + ∠CFQ = 180°

∠CFQ = 110°