Given that,
PQ ‖ RS
∠AEF = 95°
∠BHS = 110°
∠ABC = x°
∠AEF = ∠AGH = 95°(Corresponding angles)
∠AGH + ∠HGB = 180°(Linear pair)
95° + ∠HGB = 180°
∠HGB = 85°
∠BHS + ∠BHG = 180°(Linear pair)
110° + ∠BHG = 180°
∠BHG = 70°
In BHG,
∠BHG + ∠HGB + ∠GBH = 180°
70° + 95° + ∠GBH = 180°
∠GBH = 25°
Thus,
∠ABC = ∠GBH = 25°