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If 2-m× \(\frac{1}{{2}^m}\) = \(\frac{1}4\) , then \(\frac{1}{14}\)\(\{(4^m)^{\frac{1}{2}}+(\frac{1}{5^m})^{-1}\}\) is equal to

A. \(\frac{1}2\)

B. 2

C. 4

D.\(-\frac{1}4\)

1 Answer

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Best answer

2-m × 1 / 2m = 1/4 

= 1/2m × 1/2m = 1/4 

= 1/4m = 1/4 

= m = 1

1/14 {(4m)1/2 + (1/5m) -1}

= 1/14 {2 + 5}

= 1/14 × 7

=  \(\frac{1}2\)

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