Given that,
AB ‖ CD
Produce P to Q so that PQ ‖ AB ‖ CD
∠BAP + ∠APQ = 180°(Interior angle)
132° + ∠APQ = 180°
∠APQ = 48° (i)
∠APC = ∠APQ + ∠QPC
148° = 48° + ∠QPC [From (i)]
∠QPC = 100°
∠QPC + ∠PCD = 180°(Interior angles)
100° + ∠PCD = 180°
∠PCD = 80°
∠PCD + x = 180°(Linear pair)
80° + x = 180°
x = 100°