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The value of m for which \([\{(\frac{1}{{7}^2})^{-2}\}^{-\frac{1}{3}}]^{\frac{1}{4}}\) = 7m, is

A. \(-\frac{1}{3}\)

B. \(\frac{1}4\)

C. -3

D. 2

1 Answer

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Best answer

[{74} -1/3]1/4

= (1/74)1/3 × 1/4

= (1/7)1/3 = 7m

= 7-1/3 = 7m

= m = -1/3

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