​ The angles of a triangle are (x - 40)°, (x - 20)° and (1x/2 - 10)°. Find the value of x ​

Question

The angles of a triangle are (x - 40)°, (x - 20)° and \((\frac{1}{2}x-10)\)°. Find the value of x

Answer 1

Given that,

The angles of the triangle are (x – 40°), (x – 20°) and ( – 10°)

We know that,

Sum of all angles of triangle is 180°.

Therefore,

x – 40° + x – 20° + \(\frac{x}{2}\)  – 10° = 180°

2x + \(\frac{x}{2}\) – 70° = 180°

\(\frac{5x}{2}\) = 250°

5x = 250° x 2

5x = 500°

x = 100°

Therefore, x = 100°