​ If √ 2^n = 1024, then 3^2(n/4-4) = ​

Question

If \(\sqrt{2^n}\) = 1024, then \(3^{2(\frac{n}{4}-4)}\) =

A. 3

B. 9

C. 27

D. 81

Answer 1

\(\sqrt{2^n}\) = 2¹⁰

2^n/2 = 2¹⁰

\(\frac{n}{2}\) = 10

n = 20

= 3² (n / 4 – 4)

= 3² (20/4 – 4) 

= 3² = 9