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in Exponents by (30.2k points)
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If \(\frac{{3}^{5x} \times81^2 \times6561}{{3}^{2x}}\) = 37, then x =

A. 3

B. -3

C.\(\frac{1}3\)

D. \(-\frac{1}3\)

1 Answer

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Best answer

\(\frac{{3}^{5x} \times81^2 \times6561}{{3}^{2x}}\) = 37

= 35x × 38 × 38/ 32x = 37

= 35x + 16 – 2x = 37

= 5x + 16 – 2x = 7

= 3x + 16 =7

= 3x = -9

x = -3

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