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If the bisectors of the base angles of a triangle enclose an angle of 135°, prove that the triangle is a right triangle.

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Given bisector og the base angles of a triangle enclose an angle of 135°

i.e. ∠BOC = 135°

But,

135° = 90° + \(\frac{1}{2}\)∠A

\(\frac{1}{2}\)∠A = 135° – 90°

∠A = 45° (2)

= 90°

Therefore, is right angled triangle right angled at A.

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