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If sin y = x sin (a + y), then \(\cfrac{dy}{d\mathrm x} \) is

A. \(\cfrac{sin\,a}{sin\,a\,sin^2(a+y)}\)

B. \(\cfrac{sin^2\,(a+y)}{sin\,a}\)

C. sin a sin2 (a + y)

D. \(\cfrac{sin^2\,(a-y)}{sin\,a}\)

1 Answer

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Best answer

Correct option is  B. \(\cfrac{sin^2\,(a+y)}{sin\,a}\) 

sin y = x sin (a + y)

Differentiating w.r.t y we get,

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