Given,
AM perpendicular to BC
AN is bisector of ∠A
Therefore, ∠NAC = ∠NAB
In ΔABC
∠A + ∠B + ∠C = 180°
∠A + 65° + 33° = 180°
∠A = 180° – 98°
= 82°
∠NAC = ∠NAB = 41°(Therefore, AN is bisector of ∠A)
In ΔAMB
∠AMB + ∠MAB + ∠ABM = 180°
90° + ∠MAB + 65° = 180°
∠MAB + 155° = 180°
∠MAB = 25°
Therefore,
∠MAB + ∠MAN = ∠BAN
25° + ∠MAN = 41°
∠MAN = 41° – 25°
= 16°