we have,
f (x) = 2x3 - 3x2 + ax + b
Put,
x = 0
f (0) = 2 (0)3 – 3 (0)2 + a (0) + b
= 0 – 0 + 0 + b
= b
x = - 1
f (-1) = 2 (-1)3 – 3 (-1)2 + a (-1) + b
= - 2 – 3 – a + b
= - 5 – a + b
Since, x = 0 and x = -1 are roots of f (x)
f (0) = 0 and f (-1) = 0
b = 0 and - 5 – a + b = 0
= a – b = - 5
= a – 0 = - 5
= a = - 5
Therefore,
a = - 5 and b = 0