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If f(x) = x + 1, then write the value of

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f(x) = x + 1

⇒ (fof)(x) = f(x) + 1

= (x + 1) + 1

= x + 2

So, \(\frac{d}{d\text x}\)(fof)(x) = \(\frac{d}{d\text x}\)(x + 2)

= 1

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