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If y = sin-1 x + cos-1 x, find \(\cfrac{dy}{d\mathrm x} \).

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We know that  sin-1x+ cos-1x = \(\cfrac{\pi}2\)

So, here y = sin–1 x + cos–1 x

= \(\cfrac{\pi}2\) which is a constant.

Also, sin-1 x and cos-1 x exist only when -1 ≤ x ≤ 1

So, \(\cfrac{dy}{d\mathrm x} \) = 0 when x ∈ [-1, 1] and does not exist for all other values of x.

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