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If y = sin-1\(\Big(\cfrac{1-\text x^2}{1+\text x^2}\Big)\) + cos-1\(\Big(\cfrac{1-\text x^2}{1+\text x^2}\Big),\) find \(\cfrac{dy}{d\mathrm x} \).

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Hence, \(\cfrac{dy}{d\mathrm x} \) = 0, for all x ∈ R.

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