We have,
f(x) = x3 - 6x2 + 11x - 6 and g(x) = x - 3
In order to find whether polynomials g (x) = x – 3 is a factor of f (x), it is sufficient to show that f (3) = 0
Now,
f(x) = x3 - 6x2 + 11x - 6
f (3) = 33 – 6 (3)2 + 11 (3) – 6
= 27 – 54 + 33 – 6
= 60 – 60
= 0
Hence,
g (x) is a factor of f (x).