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in Triangles by (36.4k points)
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In a Δ ABC, if AB = AC and BC is produced to D such that ∠ACD = 100°, then ∠A =

A. 20°

B. 40°

C. 60°

D. 80°

1 Answer

+1 vote
by (38.0k points)
selected by
 
Best answer

∠ACB + ∠ACD = 180°

On solving we get,

∠ACB = 80°

∠ABC = ∠ACB = 80° (Angles opposite to equal sides are equal)

In ΔABC,

∠A + ∠B + ∠C = 180°

∠A + 80° + 80° = 180°

∠A = 20°

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