Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
294 views
in Mensuration by (30.2k points)
closed by

The adjacent sides of a parallelogram ABCD measure 34 cm and 20 cm, and the diagonal AC measures 42 cm. Find the area of the parallelogram.

1 Answer

+1 vote
by (28.9k points)
selected by
 
Best answer

Now in ∆ABC

AB = a = 34 cm, BC = b = 20 cm, AC = c = 42 cm 

Let a, b and c are the sides of triangle and s is 

the semi-perimeter, then its area is given by:

A = \(\sqrt{s(s-a)(s-b)(s-c)}\)where s = \(\frac{a+b+c}2\)

s = \(\frac{a+b+c}2\) = \(\frac{34+20+42}2\) = 48

A = \(\sqrt{48(48-34)(48-20)(48-42)}\) cm2

a = \(\sqrt{48\times14\times28\times6}\) = 336 cm2

Hence, area of Parallelograme ABCD =2 × 336 =672 cm2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...