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in Triangles by (38.0k points)
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In Fig., the measure of ∠B’AC’ is

A. 50°

B. 60°

C. 70°

D. 80°

1 Answer

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by (36.4k points)
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Best answer

In ΔABC and ΔA'B'C',

AB = A'B' (Given)

∠B = ∠B'(Given)

BC = B'C' (Given)

Hence, by S.A.S. theorem,

ΔABC ≅ ΔA'B'C'

Therefore,

By c.p.c.t

∠A = ∠A'

3x = 2x +20

x = 20°

Therefore angle A' = 2x +20

= 60°

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