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Find the area of a triangle whose sides are 3 cm, 4 cm, and 5 cm respectively.

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Let a, b and c are the sides of triangle and s is 

the semi-perimeter, then its area is given by:

A = \(\sqrt{s(s-a)(s-b)(s-c)}\)where s = \(\frac{a+b+c}2\)[Heron’s Formula]

s = \(\frac{a+b+c}2\) = \(\frac{3+4+5}2\) = 6

A = \(\sqrt{6(6-3)(6-4)(6-5)}\)

A = \(\sqrt{6\times3\times2\times1}\) = 6 cm2

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