Question

If ABCD is a rectangle with ∠BAC=32°, find the measure of ∠DBC.

Answer 1

Given, 

ABCD is a rectangle

∠BAC = 32°

∵ We know that diagonals of a rectangle bisects each other 

Hence, 

AO = BO 

And, 

∠DBA = ∠BAC = 32° 

(angles infront of same sides) 

∵ ∠DBC+∠DBA = 90° 

∴ ∠DBC = 90° - 32° = 58°