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in Quadrilaterals by (26.9k points)
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In a parallelogram ABCD, if ∠DAB = 75° and ∠DBC = 60°, then ∠BDC =

A. 75° 

B. 60° 

C. 45° 

D. 55°

1 Answer

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by (27.3k points)
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Best answer

Option : (C)

Given, 

In parallelogram ABCD, 

∠DAB = 75°

∠DBC = 60° 

∵ ∠DAB= ∠BCD 

[opposite angles of parallelogram] 

∠BCD = 75° 

Now, 

In ∆BDC,

= ∠DBC+∠BDC+∠BCD = 180° 

= 60°+∠BDC+75° = 180° 

=∠BDC = 180° - 135° 

=∠BDC = 45°.

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