Given,
Diameter of cylindrical bowl = 7 cm
So radius of bowl = \(\cfrac72\) cm
Height of soup in bowl = 4 cm
Volume of soup in 1 bowl = πr2h
= \(\cfrac{22}7\times\cfrac{7}2\times\cfrac{7}2\)\(\times\)4 = 154 cm3
For 250 patients volume of soup prepared = 250 × 154 = 38500 cm3
= \(\cfrac{38500}{1000}\) = 38.5 liter