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Find the median of the following observations: 46, 64, 87, 41, 58, 77, 35, 90, 55, 92, 33. If 92 is replaced by 99 and 41 by 43 in the above data, find the new median?

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Given, numbers are:

46, 64, 87, 41, 58, 77, 35, 90, 55, 92, 33

Arrange in increasing order:

33, 35, 41, 46, 55, 58, 64, 77, 87, 90, 92

n = 11 (odd)

Therefore, median \(=\frac{n + 1}{2}\)

\(=\frac{11 + 1}{2}\)

\(=\frac{12}{2}\) = 6th value

= 58

If 92 is replaced by 99 and 41 by 43, then the new values are:

33, 35, 43, 46, 55, 58, 64, 77, 81, 90, 99

Therefore, n = 11 (odd)

New median \(=\frac{n + 1}{2}\) value

\(=\frac{11 + 1}{2}\)

= 6th value = 58

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