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Construct Δ ABC with BC = 7.5 cm, AC = 5 cm and m∠ C = 60

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To constructΔ ABC where BC = 7.5 cm, AC = 5 cm and m C = 60 .

Steps of construction:

(a) Draw a line segment BC = 7.5 cm.

(b) At point C, draw an angle of 60 with the help of protractor, i.e.,

 XCB = 60 .

(c) Taking C as centre and radius 5 cm, draw an arc, which cuts XC at the point A.

(d) Join AB

It is the required triangle ABC.

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