Option : (A)
Given,
ABCD is a parallelogram,
P is mid point of side BC
∠BAP = ∠DAP
AD = 10cm
∵ AD || BC
∠DAP = ∠APB
[alternate angles]
∠DAP = ∠BAP
AB = BP
(side opposite to equal angles)
= BP = \(\frac{1}{2}\)BC
∴ AB = \(\frac{1}{2}\)BC
= \(\frac{1}{2}\) x 10
= 5 cm
AB = CD = 5cm
(sides of parallelogram)
Hence,
CD = 5 cm