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If the median of 33m 28, 20, 25, 34, x is 29, find the maximum possible value of x.

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Best answer

There are 6 observations i.e. even no. of observations

So, median will be:

\(\frac{(3rd\,observation\,+\,4^{th}\,observation)}{2}\)

Arranging in increasing order:

20, 25, 28, x, 33, 34

If we put any other number at 4th position the n, we will not get the median = 29

So, \(\frac{28+x}{2}=29\)

28 + x = 58

x = 58 – 28

= 30

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