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What is the largest number that divides 626, 3127 and 15628 and leaves remainders of 1, 2 and 3 respectively?

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The new numbers after subtracting remainders are:

626 - 1 = 625

3127 - 2 = 3125

15628 - 3 = 15625

Prime factors of 625 = 5 × 5 × 5 × 5

Prime factors of 3125 = 5 × 5 × 5 × 5 × 5

Prime factors of 15625 = 5 × 5 × 5 × 5 × 5 × 5

Therefore HCF of 625, 3125 and 15625 is:

5 × 5 × 5 × 5 = 625

Hence the largest number which divides 626, 3127 and 15628 and leaves remainders of 1, 2 and 3 respectively is 625

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