To find : the average number of misprints per page.
Use the shortcut method to find the mean of given data.For that,Let the assumed mean be (A) = 2,The deviation of values xi from assumed mean be di = xi – A.
Now to find the mean:First multiply the frequencies in column (ii) with the value of deviations in column (iii) as fidi.
No. of misprints per pages (xi) |
No. of pages (fi) |
di = xi - A = xi - 2 |
fidi |
0 |
154 |
-2 |
-308 |
1 |
95 |
-1 |
-95 |
2 |
36 |
0 |
0 |
3 |
9 |
1 |
9 |
4 |
5 |
2 |
10 |
5 |
1 |
3 |
3 |
|
N = 300 |
|
\(\sum\)fidi = -381 |
Now add the sum of all entries in column (iii) to obtain \(\displaystyle\sum_{i=1}^{n} f_id_i\)
and the sum of all frequencies in the column (ii) to obtain \(\displaystyle\sum_{i=1}^{n} f_id_i=N\)
So,
Average number of misprints per day = A + \(\frac{\sum f_id_i}{N}\)
where, N = total number of observations
⇒ Mean = 2 + \(\frac{-381}{300}\)
Mean = \(\frac{600-381}{300}\)
Mean = \(\frac{219}{300}\)
Mean = 0.73