**To construct:** A right angled triangle PQR where m∠ Q = 90 , QR = 8 cm and PQ = 10 cm.

**Steps of construction:**

(a) Draw a line segment QR = 8 cm.

(b) At point Q, draw QX⊥ QR.

(c) Taking R as centre, draw an arc of radius 10 cm.

(d) This arc cuts QX at point P.

(e) Join PQ.

It is the required right angled triangle PQR.