Question

In a cricket match, a batsman hits a boundry 6 times out of 30 balls he plays.

Find the probability that on a ball played :

(i) He hits boundry.

(ii) He does not hit a boundry.

Answer 1

Given,

Number of times batsman hits the boundry = 6

Total balls played = 30

Number of times that batsman does not hit the boundry = 30 - 6 = 24

Probability (number of times he hits a boundry) \(=\frac{\text{number of times he hits a boundry}}{\text{total number of balls played}}\) \(=\frac{6}{30}=\frac{1}{5}\)

Probability (number of times he does not hits a boundry) \(=\frac{\text{number of times he does not hits a boundry}}{\text{total number of balls played}}\) \(=\frac{24}{30}=\frac{4}{5}\)