Length of stick = 10cm
Length of shadow stick= 8cm
Length of shadow of tower = hcm
In ΔABC and ΔPQR
∠B = ∠C = 90º And ∠C = ∠R (angular elevation of sum)
Then ΔABC ~ ΔPQR (by AA similarty)
So, \(\frac{AB}{PQ}\) = \(\frac{BC}{QR}\)
Or\(\frac{10 cm}{8 cm}\) = \(\frac{H}{3000}\)
Or h= \(\frac{10}{8}\) x 3000
Or 3750 cm
Or 37.5 m