Let the assumed mean (A) = 150
Class interval |
Mid value (xi) |
di = xi -150 |
ui= \(\frac{xi-150}{20}\) |
Frequency (fi) |
fiui |
100 - 120 |
110 |
-40 |
-2 |
12 |
-24 |
120 - 140 |
130 |
-20 |
-1 |
14 |
-14 |
140 - 160 |
150 |
0 |
0 |
8 |
0 |
160 - 180 |
170 |
20 |
1 |
6 |
6 |
180 - 200 |
190 |
40 |
2 |
10 |
20 |
|
|
|
|
N = 50 |
\(\sum\)fiui = - 12 |
We have,
A = 150
h = 20
Mean = A + h \(\times\frac{\sum f_iu_i}{N}\)
\(=150+20\times\frac{-12}{50}\)
\(=150\,-\frac{24}{5}=150-4.8\)
\(=145.2\)