Since it is given that p and q are prime positive integer.
Let us assume that √p + √q is a rational number of the form \(\frac{a}{b}\),
Squaring both sides we get,
Apply the formula (a - b)2 = a2 + b2 - 2ab
Since p, q are integers therefore \(\cfrac{a^2-pb^2-qb^2}{ab}\) is rational number
But we know √p is irrational number,
Therefore it is a contradiction.
Hence √p - √q is irrational