Question

If α and β are the zeros of the quadratic polynomial p(s) = 3s² - 6s + 4, find the value of \(\frac{\alpha}{\beta}\) + \(\frac{\beta}{\alpha}\) + 2(\(\frac{1}{\alpha}\) + \(\frac{1}{\beta}\)) + 3αβ

Answer 1

Let and β are the roots of the given equation

Sum of the roots

= -( -6/3) = 2

Using (a + b)² = a² + b² + 2ab