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Construct a ΔABC in which BC = 3.4 cm, AB - AC = 1.5 cm and ∠B = 45°.

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(1) Draw a line segment BC = 3.4cm. 

Using a protractor, draw ∠CBD = 45°. 

Join BD and extend it.

(2) Taking B as the center and radius = 1.5cm, draw an arc, intersecting BD at point P. 

Join PC

(3) Taking P as the center and radius greater than \(\frac{PC}{2}\), draw arcs on each side of PC.

Now,

Taking C as the center and same radius, draw arcs, intersecting the previous arcs at points Q and R. 

Join and extend QR. 

Extended QR intersects extended line segment DB at point A. 

Join AC.

(4) ∆ABC is the required triangle.

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