(1) Draw a line segment BC = 3.4cm.
Using a protractor, draw ∠CBD = 45°.
Join BD and extend it.
(2) Taking B as the center and radius = 1.5cm, draw an arc, intersecting BD at point P.
Join PC
(3) Taking P as the center and radius greater than \(\frac{PC}{2}\), draw arcs on each side of PC.
Now,
Taking C as the center and same radius, draw arcs, intersecting the previous arcs at points Q and R.
Join and extend QR.
Extended QR intersects extended line segment DB at point A.
Join AC.
(4) ∆ABC is the required triangle.