From Direct method:
Class interval |
Mid value (xi) |
fi |
fixi |
0 - 10 |
5 |
20 |
100 |
10 - 20 |
15 |
24 |
360 |
20 - 30 |
25 |
40 |
1000 |
40 - 50 |
45 |
20 |
900 |
|
|
|
|
|
|
N = 140 |
\(\sum\)fixi = 3620 |
Mean = \(\frac{\sum f_ix_i}{N}\)
\(=\frac{3620}{140}=25.857\)
Assumed mean method:
let assumed mean (A) = 25
Mean = A + \(\frac{\sum f_iu_i}{N}\)
Class interval |
Mid value (xi) |
ui = xi - A |
fi |
fiui |
0 - 10 |
5 |
-20 |
20 |
-400 |
10 - 20 |
15 |
-10 |
24 |
-240 |
20 - 30 |
25 |
0 |
40 |
0 |
30 - 40 |
35 |
10 |
36 |
360 |
40 - 50 |
45 |
20 |
20 |
400 |
|
|
|
N = 140 |
\(\sum\)fiui = 120 |
Mean = A + \(\frac{\sum f_ix_i}{N}\)
\(=25+\frac{120}{140}=25+0.857\)
\(=25.857\)
Step deviation method: Let the assumed mean (A) = 25
Class interval |
Mid value (xi) |
di = xi - A = xi - 25 |
ui = \(\frac{xi-25}{10}\) |
Frequency (fi) |
fiui |
0 - 10 |
5 |
-20 |
-2 |
20 |
-40 |
10 - 20 |
15 |
-10 |
-1 |
24 |
-24 |
20 - 30 |
25 |
0 |
0 |
40 |
0 |
30 - 40 |
35 |
10 |
1 |
36 |
36 |
40 - 50 |
45 |
20 |
2 |
20 |
40 |
|
|
|
|
N = 140 |
\(\sum\)fiui = 12 |
Mean = A + \(\frac{\sum f_iu_i}{N}\times h\)
\(=25+0.857=25.857\)
\(=25+\frac{12}{140}\times10\)
\(=25+0.857=25.857\)