Given,
Mean = 18
Let missing frequency be V
Class interval |
Mid value (xi) |
fi |
fixi |
11 - 13 |
12 |
7 |
84 |
13 - 15 |
14 |
6 |
84 |
15 - 17 |
16 |
9 |
144 |
19 - 21 |
20 |
V |
20V |
21 - 23 |
22 |
5 |
110 |
23 - 25 |
24 |
4 |
56 |
|
|
N = 44 + V |
\(\sum\)fixi = 752 + 20V |
Mean = \(\frac{\sum f_ix_i}{N}\)
\(18 = \frac{752+20V}{44+V}\)
792 + 18V = 752 + 20V
792 – 752 = 20V – 18V
40 = 2V
V = 20