Given, Polynomial
2y2 + 7y + 5
Zeroes = a, 13
Here,
a = 2 b = 7 c = 5
Lets take α and β are two zero,
So sum of the zeroes will be,
α + β = – b/a = – 7/2
Product of the zeroes = α. β = c/a = 5/2
Now put the values,
α + β + αβ = (α + β) αβ
= – 7/2 + 5/2 = – 2/2 = – 1