Class interval (exclusive) 
Class interval (inclusive) 
Frequency 
Cumulative frequency 
55  64 
54.5  64.5 
1 
1 
65  74 
64.5  74.5 
2 
3 
75  84 
74.5  84.5 
9 
12 
85  94 
84.5  94.5 
22 
34 (F) 
95  104 
94.5  104.5 
33 (f) 
37 
105  114 
104.5  114.5 
22 
89 
115  124 
114.5  114.5 
8 
97 
125  134 
114.5  124.5 
2 
99 
135  144 
134.5  144.5 
1 
100 


N = 100 

We have,
N = 100
\(\frac{N}{2}=\frac{100}{2}=50\)
The cumulative frequency just greater than \(\frac{N}{2}\) s 67 then the median class 94.5104.5 such that,
l = 94.5, f = 33, F = 34, h = 104.5 – 94.5 = 10
Median = I + \(\frac{\frac{N}{2}F}{f}\times h\)
\(=94.5+\frac{5034}{33}\times10\)
\(=94.5+\frac{16}{33}\times10\)
\(=94.5+4.85=99.35\)