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in Polynomials by (36.4k points)
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If α, β, γ are the zeros of the polynomial f(x) = x3 – px2 + qx – r, then \(\frac{1}{αβ}\) + \(\frac{1}{βγ}\)\(\frac{1}{\gamma \alpha}\) =

A. \(\frac{r}{p}\)

B. \(\frac{p}{r}\)

C. - \(\frac{p}{r}\)

D. - \(\frac{r}{p}\)

1 Answer

+1 vote
by (38.0k points)
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Best answer

Given,

f(x) = x3 – px2 + qx – r

α, β and y are the Zeros,

α + β + y = – p

αβ + βy + yα = – q

αβy = – r

1/αβ + 1/βy + 1/yα = p/r

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