**Given,**

Median = 46

Then, median class = 40-50

**Therefore, **

l = 40, h = 10, f = 65, F = 42 + x

Median = l + \(\frac{\frac{N}{2}-F}{f}\)

\(46=40+\frac{115-(42+x)}{65}\times 10\)

\(\frac{6\times65}{10}=73-\times\)

39 = 73 – x

x = 73 – 39

x = 34

**Given, **

N = 230

= 12 + 30 + 34 + 65 + y + 25 + 18 = 230

= 184 + y = 230

= y = 230 – 184 = 46

Mean = \(\frac{\sum fx}{N}\)

\(=\frac{10550}{230}=45.87\)