Given,
Median = 46
Then, median class = 40-50
Therefore,
l = 40, h = 10, f = 65, F = 42 + x
Median = l + \(\frac{\frac{N}{2}-F}{f}\)
\(46=40+\frac{115-(42+x)}{65}\times 10\)
\(\frac{6\times65}{10}=73-\times\)
39 = 73 – x
x = 73 – 39
x = 34
Given,
N = 230
= 12 + 30 + 34 + 65 + y + 25 + 18 = 230
= 184 + y = 230
= y = 230 – 184 = 46
Mean = \(\frac{\sum fx}{N}\)
\(=\frac{10550}{230}=45.87\)