Given:
The frequency table.
To find:
The missing frequencies f1 and f2 .
Solution:
Construct a table to calculate cumulative frequencies,The table is shown below:
As it lies in the interval 20-30,
So,
median class is 20-30
Now, l, lower class = 20, frequency of median class, f = 20, Cumulative frequency of class preceding the median class, F = 5 + f1, height of class, h = 10N is 60,
we know,
f1 = 25 – 17
f1 = 8
Given,
sum of frequencies = 60
i.e. 5 + f1 + 20 + 15 + f2 + 5 = 60Put the value of f1
therefore, 5 + 8 + 20 + 15 + f2 + 5 = 60
hence,
f2 = 7
Therefore,
f1 = 8 and f2 = 7